Trinidad and Tobago’s Calypso Rose, real name Linda Mcartha Sandy Lewis will perform at Coachella, one of the world’s biggest music and art festivals.
This is Rose’s first time performing at the event which is scheduled to take place in Southern California from April 12 to April 14 and from April 19 to April 21.
The veteran singer will be a part of a star-studded line-up of artistes which include Childish Gambino, Janelle Monae, Diplo among others.
On Thursday, Rose went on her Instagram and commented on her selection for the celebrity-packed event.
“So excited, I can’t wait to sing, dance and enjoy this time with all of you.”
Every year, the festival draws thousands of music and art lovers in various parts of the world. This year, fans will also enjoy hits from musical giants such as Ariana Grande, Whiz Khalifa, Dj Kahlid, Pusha-T among others.
Some other local stars that have performed previously at Coachella include Machel Montano, Ian “Bunji Garlin” Alvarez and his wife, Fay Ann.
At 78, Rose continues to add more accolades to her very busy musical career.
Dubbed the calypso queen of the world, she was recently awarded the grand prize for World Music Award at the Sacem Grand Prix in France and has seen a resurgence in her career since she released her album Far From Home in 2016.
She has toured throughout Europe and in 2017 won the World Album Of The Year at the Victoire de la Musique, considered the French equivalent of the Grammy Awards.
In May last year, the seasoned singer released her follow up album So Calypso.